response = HttpResponse(mimetype='audio/mpeg')
response['Content-Disposition'] = 'attachment;
filename=%s' % smart_str(file_name)
response['Accept-Ranges'] = 'bytes'
response['X-Sendfile'] = smart_str(path_to_file)
return response
上面这段代码是在stackoverflow上看到的,但是只能下载服务器上本地资源,请教各位如何下载网络上的资料链接,如http://example.com/mp3/**.mp3