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PHP MySQL Count总问题

Kyocera Alerts • 5 年前 • 1581 次点击  

SELECT
    GROUP_CONCAT(DISTINCT nextgenorder_companyname) AS nextgenorder_companyname,
    GROUP_CONCAT(DISTINCT nextgenorder_company_entity) AS nextgenorder_company_entity,
    GROUP_CONCAT(DISTINCT nextgenorder_ordernumber) AS nextgenorder_ordernumber,
    GROUP_CONCAT(DISTINCT nextgenorder_deliverydate) AS nextgenorder_deliverydate
FROM nextgenorders2
WHERE nextgenorder_deliverydate='2020-11-11'
GROUP BY SUBSTRING_INDEX(REPLACE(nextgenorder_companyname, '/', ' '), ' ',1)
ORDER BY SUBSTRING_INDEX(REPLACE(nextgenorder_companyname, '/', ' '), ' ',1)

SQL Fiddle Example

enter image description here

我试过这个:

SELECT 
count(DISTINCT nextgenorder_company_entity) as company, 
nextgenorder_deliverydate as ShipDate 
FROM nextgenorders2 
WHERE nextgenorder_deliverydate='2020-11-11' 
    GROUP BY nextgenorder_deliverydate

SQL Fiddle Example

SELECT GROUP_CONCAT(nextgenorder_companyname) AS nextgenorder_companyname,
GROUP_CONCAT(nextgenorder_deliverydate) nextgenorder_deliverydate
  FROM
(
  SELECT COUNT(*) Total
    FROM nextgenorders2
  WHERE nextgenorder_deliverydate='2020-11-11'
 GROUP BY SUBSTRING_INDEX(REPLACE(nextgenorder_companyname, '/', ' '), ' ',1)

) q
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文章 [ 1 ]  |  最新文章 5 年前
Gordon Linoff
Reply   •   1 楼
Gordon Linoff    5 年前

有一个表达式可以从数据库的列中提取“公司名称”。

count(distinct) :

SELECT count(DISTINCT SUBSTRING_INDEX(REPLACE(nextgenorder_companyname, '/', ' '), ' ',1)
            ) as company, 
       nextgenorder_deliverydate as ShipDate 
FROM nextgenorders2 
WHERE nextgenorder_deliverydate = '2020-11-11' 
GROUP BY nextgenorder_deliverydate;

Here 是db<gt;小提琴。