我试图创建一个函数,该函数将嵌套数组(dict/list以任何顺序)和一个键名作为参数,并在列表中返回该键的所有值。
my_key = "Items"
my_dict = [{'z': 0, 'x': 0, 'y': 0, 'Items': [{'Slot': 1, 'id': 'minecraft:rail', 'Count': 1}, {'Slot': 2, 'id': 'minecraft:white_shulker_box', 'tag': {'BlockEntityTag': {'id': 'minecraft:shulker_box', 'Items': [{'Slot': 0, 'Count': 1, 'tag': {'Items': [{'id': 'minecraft:amethyst_shard', 'Count': 1}]}, 'id': 'minecraft:bundle'}]}}, 'Count': 1}]}]
def recursive_lookup(data, key):
if isinstance(data, list):
for i in data:
recursive_lookup(i, key)
elif isinstance(data, dict):
for i, v in data.items():
if i == key:
print(f'{v = }')
if isinstance(v, list) or isinstance(v, dict): recursive_lookup(v, key)
print(recursive_lookup(my_dict, my_key))
目前,它会在
print(f'{v = }')
.如何将其存储在列表中并作为函数返回传递?
