今天分享一个前几天构建的小应用程序，用来从命令行搜索emoji表情符号。它可以通过OS命令行来完成，而且不必单击任何东西即可获得我的表情符号，更加便捷。$ emo
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> snake beer fire ninja
Copying 🐍 🍺 🔥 🥷 to clipboard
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> q
Bye
至此，我的剪贴板上所有4个表情符号都写好了，在键盘输入Cmd + V即可。git clone git@github.com:PyBites-Open-Source/emojisearcher.git
cd emojisearcher
poetry install
poetry run emo
poetry使依赖项管理变得轻而易举，最后一个命令（别名）实际上有效，因为我将其放在pyproject.toml文件中：[tool.poetry.scripts]
emo = "emojisearcher.script:main"
您也可以通过添加以下shell别名来使调用命令更短（就像我在第一个示例中一样）：$ alias emo
alias emo='cd YOUR_PATH/emojisearcher && poetry run emo'
由于有了poetry new，文件夹结构从一开始就遵循了公认的最佳做法。我喜欢将测试文件放在专用的tests /文件夹中。我使用emoji库中的EMOJI_UNICODE常量来查找emoji表情：
...
EMOJI_MAPPING = EMOJI_UNICODE[LANGUAGE]
...
def get_emojis_for_word(
word: str, emoji_mapping: dict[str, str] = EMOJI_MAPPING
) -> list[str]:
return [emo for name, emo in emoji_mapping.items() if word in name]
然后我使用pyperclip复制到操作系统的剪贴板中：from pyperclip import copy
...
def copy_emojis_to_clipboard(matches: list[str]) -> None:
all_matching_emojis = ' '.join(matches)
print(f"Copying {all_matching_emojis} to clipboard")
copy(all_matching_emojis)
感谢这个库的作者AlSweigart，这是一个很酷的程序包。在这种情况下，我通过user_select_emoji函数进入交互模式。我想用一种创新的方式来触发此交互模式，为此选择了信号字符（SIGNAL_CHAR）：如果用户的搜索字符串以点（.）结尾，它将进入交互模式。$ emo
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> snake
Copying 🐍 to clipboard
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> flag
Copying 🏴 to clipboard
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> flag.
1 🏴
2 🏁
3 📪
4 📫
5 🎌
6 ⛳
7 📭
8 📬
9 🏴☠️
10 🏳️🌈
11 🏳️⚧️
12 🚩
13 🏳
Select the number of the emoji you want: 12
Copying 🚩 to clipboard
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> q
Bye
键入“snake（蛇）”后出现的emoji不会出错，但是对于“flag（旗帜）”，它默认选择12个匹配项中的第一个（对于“heart（心脏）”，我们会得到130个匹配的表情符号！），这里我想手动选择一个，因此键入点"."，以做出进一步的选择。-
@ pytest.mark.parametrize非常好，可以使您的测试代码更加简洁。 - 我测试了使用
@patch（“ builtins.input”，side_effect = ['a'，10，2，'q']的交互模式模拟input的方法。side_effect中的列表包含将“double” input的参数。这等效于以下内容（在键入tree之后。）：
$ emo
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> tree.
1 🎄
2 🌳
3 🌲
4 🌴
5 🎋
Select the number of the emoji you want: a
a is not an integer.
1 🎄
2 🌳
3 🌲
4 🌴
5 🎋
Select the number of the emoji you want: 10
10 is not a valid option.
1 🎄
2 🌳
3 🌲
4 🌴
5 🎋
Select the number of the emoji you want: 2
Copying 🌳 to clipboard
------------------------------------------------------------------------------------
Type one or more emoji related words ...
End a word with a . if you want to select an emoji if there are multiple
matches, otherwise the first match will be picked. Type 'q' to exit.
> q
Bye
- 测试代码时，一种有用的技术是删除所有常见的前导空白。您可以为此使用
textwrap.dedent，但是在这里我使用了替代的inspect.cleandoc。
感谢toml文件中[tool.poetry]中的一些基本元数据，发布到PyP非常简单：poetry build
poetry publish
（首先使用--repository of publish在测试PyPI上尝试一下，看是否一切正常。）如果您喜欢这个项目，请在Github上给它加星标，很高兴能收到反馈。https://github.com/PyBites-Open-Source/emojisearcher
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